KADD 2022 Laboratorium 5 ENFrom Łukasz Graczykowski
ExerciseMeasurements of three physical observables Dane1.dat, Dane2.dat and Dane3.dat.
Variables
Y2 = 3 + 0.5 X1 + 4 X2 Please calculate:
Attention
ifstream ifile; ifile.open("dane.dat"); double val; while(ifile>>val) { cout<<val<<endl; } ifile.close();
double x1min = 1.5, x1max = 5.0; double x2min = 0.0, x2max = 3.0; double x3min = 4.0, x3max = 16.0; TH2D *h12 = new TH2D("h12","Hist12",100,x1min,x1max,100,x2min,x2max); TH2D *h13 = new TH2D("h13","Hist13",100,x1min,x1max,100,x3min,x3max); TH2D *h23 = new TH2D("h13","Hist23",100,x2min,x2max,100,x3min,x3max); ResultsOutput: X1=3.00691, u(X1)=0.495242 X2=2.00581, u(X1)=0.40909 X3=9.97287, u(X3)=1.98102 rho(X1,X2)=0.156132 rho(X1,X3)=-0.00698853 rho(X2,X3)=0.00875851 after rounding to 2 significant digits: X1=3.01, u(X1)=0.50 X2=2.01, u(X1)=0.41 X3=9.97, u(X3)=1.98 This is the matrix of covariance for X 3x3 matrix is as follows | 0 | 1 | 2 | -------------------------------------------- 0 | 0.2453 0.0316 -0.006855 1 | 0.0316 0.1674 0.0071 2 | -0.006855 0.0071 3.924 This is the matrix of covariance for Y 2x2 matrix is as follows | 0 | 1 | ------------------------------- 0 | 9.765 3.949 1 | 3.949 2.865 Y1=26.0157, u(Y1)=3.1249 Y2=12.5267, u(Y2)=1.6927404 rho(Y1,Y2)=0.746574 rho(Y2,Y1)=0.746574 after rounding to 2 significant digits: Y1=26.02, u(Y1)=3.13 Y2=12.53, u(Y2)=1.70 |